A satellite of mass m,revolving around the Ea | vedclass

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(C) The kinetic energy of the satellite is given by $E = \frac{1}{2}mv^{2}$.From this,we can express the velocity $v$ as $v = \sqrt{\frac{2E}{m}}$.The

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$(2mEr^{2})^{\frac{1}{2}}$

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(C) The kinetic energy of the satellite is given by $E = \frac{1}{2}mv^{2}$.From this,we can express the velocity $v$ as $v = \sqrt{\frac{2E}{m}}$.The angular momentum $L$ of a particle moving in a circular orbit of radius $r$ is defined as $L = mvr$.Substituting the expression for $v$ into the formula for $L$:$L = m \cdot \sqrt{\frac{2E}{m}} \cdot r$$L = \sqrt{m^{2} \cdot \frac{2E}{m} \cdot r^{2}}$$L = \sqrt{2mEr^{2}}$$L = (2mEr^{2})^{\frac{1}{2}}$.

$A$ satellite of mass $m$,revolving around the Earth of radius $r$,has kinetic energy $E$. Its angular momentum is:

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