Two satellites $A$ and $B$,having a ratio of masses $3 : 1$,are in circular orbits of radius $r$ and $4r$ respectively. Calculate the ratio of the total mechanical energy of $A$ and $B$.

When a satellite going round the Earth in a circular orbit of radius $r$ and speed $v$ loses some of its energy,then $r$ and $v$ change as:

The total energy of a circularly orbiting satellite is

Two satellites $A$ and $B$,with a mass ratio of $3:1$,are in circular orbits of radii $r$ and $4r$ respectively. The ratio of the total mechanical energy of $A$ to $B$ is:

For a satellite,if the time of revolution is $T$,then its $K.E.$ is proportional to

$A$ star like the sun has several bodies moving around it at different distances. Consider that all of them are moving in circular orbits. Let $r$ be the distance of the body from the centre of the star and let its linear velocity be $v$,angular velocity $\omega$,kinetic energy $K$,gravitational potential energy $U$,total energy $E$ and angular momentum $l$. As the radius $r$ of the orbit increases,determine which of the above quantities increase and which ones decrease.