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(C) The total energy $(E)$ of a satellite in a circular orbit of radius $r$ is given by $E = -\frac{GMm}{2r}$.When the satellite loses energy,its tota

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$r$ will decrease and $v$ will increase

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(C) The total energy $(E)$ of a satellite in a circular orbit of radius $r$ is given by $E = -\frac{GMm}{2r}$.When the satellite loses energy,its total energy becomes more negative (i.e.,the magnitude of the binding energy increases,but the total energy decreases).Since $E = -\frac{GMm}{2r}$,for $E$ to decrease (become more negative),the radius $r$ must decrease.The orbital speed of a satellite is given by $v = \sqrt{\frac{GM}{r}}$.As the radius $r$ decreases,the orbital speed $v$ must increase.Therefore,$r$ will decrease and $v$ will increase.

When a satellite going round the Earth in a circular orbit of radius $r$ and speed $v$ loses some of its energy,then $r$ and $v$ change as:

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