Binding energy of a revolving satellite at he | vedclass

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(B) The binding energy $(BE)$ of a satellite is defined as the minimum energy required to remove the satellite from its orbit to infinity.For a satell

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$-7 	imes 10^8 \ J$

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(B) The binding energy $(BE)$ of a satellite is defined as the minimum energy required to remove the satellite from its orbit to infinity.For a satellite of mass $m$ at a distance $r = R + h$ from the center of the Earth,the potential energy is $U = -\frac{GMm}{r}$.The total energy of the satellite is $E = K + U = -\frac{GMm}{2r}$.The binding energy is the negative of the total energy: $BE = -E = \frac{GMm}{2r}$.Comparing $BE$ and $U$,we see that $U = -2 	imes BE$.Given $BE = 3.5 	imes 10^8 \ J$,the potential energy is $U = -2 	imes (3.5 	imes 10^8 \ J) = -7 	imes 10^8 \ J$.

Binding energy of a revolving satellite at height $h$ is $3.5 \times 10^8 \ J$. Its potential energy is

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