Fill in the blanks:
$(a)$ The value of gravitational intensity at the center of the Earth is ..... .
$(b)$ The potential energy of a satellite is $-8 \times 10^9 \, J$,then its binding energy is ............ .
$(c)$ Kepler's second law regarding the constancy of the areal velocity of a planet is a consequence of the law of conservation of .......... .

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) At the center of the Earth,the gravitational field intensity is $0$ because the mass enclosed within a sphere of radius $r=0$ is zero.
$(b)$ The binding energy $(BE)$ of a satellite is defined as the negative of its total mechanical energy. Since the total energy $E = -|PE|/2$ is not given,we use the relation $BE = -E$. For a satellite,$PE = 2E$. Given $PE = -8 \times 10^9 \, J$,then $E = -4 \times 10^9 \, J$. Thus,$BE = -(-4 \times 10^9 \, J) = 4 \times 10^9 \, J$. However,if the question implies the total energy is $-8 \times 10^9 \, J$,then $BE = 8 \times 10^9 \, J$. Assuming the standard convention where $PE$ is given,the binding energy is $4 \times 10^9 \, J$. If the value provided is the total energy,it is $8 \times 10^9 \, J$.
$(c)$ Kepler's second law (law of areas) is a direct consequence of the law of conservation of angular momentum.

Explore More

Similar Questions

As we move towards the centre of the Sun,what happens to its physical properties?

The orbital velocity of a body near the surface of a planet $A$ is equal to the escape velocity of a body from the planet $B$. If the masses of planets $A$ and $B$ are the same,the ratio of their radii is

Particles of mass $100 \, g$ each are placed at the vertices of an equilateral triangle of side $20 \, cm$. How much work must be done to increase the separation between them to infinity?

If a tunnel is cut at any orientation through the Earth,a ball released from one end will reach the other end in time ........ $\text{min}$ (neglect Earth's rotation).

Match the column $-I$ with column $-II$ for a satellite in circular orbit:
Column $-I$Column $-II$
$(A)$ Kinetic energy$(p)$ $-\frac{GM_Em}{2r}$
$(B)$ Potential energy$(q)$ $\sqrt{\frac{GM_E}{r}}$
$(C)$ Total energy$(r)$ $-\frac{GM_Em}{r}$
$(D)$ Orbital velocity$(s)$ $\frac{GM_Em}{2r}$

(where $M_E$ is the mass of the earth,$m$ is the mass of the satellite,and $r$ is the radius of the orbit)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo