Easy
How is the angular node determined? State the number of angular nodes for $s, p, d,$ and $f$ orbitals.
(N/A) The number of angular nodes is determined by the azimuthal quantum number,$l$.
For $s$ orbital: $l = 0$,therefore $0$ angular node.
For $p$ orbital: $l = 1$,therefore $1$ angular node.
For $d$ orbital: $l = 2$,therefore $2$ angular nodes.
For $f$ orbital: $l = 3$,therefore $3$ angular nodes.
For $s$ orbital: $l = 0$,therefore $0$ angular node.
For $p$ orbital: $l = 1$,therefore $1$ angular node.
For $d$ orbital: $l = 2$,therefore $2$ angular nodes.
For $f$ orbital: $l = 3$,therefore $3$ angular nodes.
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Similar Questions
In a multi-electron atom,which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields?
$1. n = 1, l = 0, m = 0$
$2. n = 2, l = 0, m = 0$
$3. n = 2, l = 1, m = 1$
$4. n = 3, l = 2, m = 0$
$5. n = 3, l = 2, m = 0$
$1. n = 1, l = 0, m = 0$
$2. n = 2, l = 0, m = 0$
$3. n = 2, l = 1, m = 1$
$4. n = 3, l = 2, m = 0$
$5. n = 3, l = 2, m = 0$
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$(i) n = 4, l = 1$
$(ii) n = 4, l = 0$
$(iii) n = 3, l = 2$
$(iv) n = 3, l = 1$
Arrange them in the increasing order of their energy.
$(i) n = 4, l = 1$
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$(iii) n = 3, l = 2$
$(iv) n = 3, l = 1$
Arrange them in the increasing order of their energy.
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View SolutionWrite about $p$-orbitals.
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