What are the spins of the two electrons in He | vedclass

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(C) According to the Pauli Exclusion Principle,no two electrons in an atom can have the same set of all four quantum numbers. For Helium ($He$,atomic

Vedclass · Accepted Answer

$+1/2$ and $-1/2$

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(C) According to the Pauli Exclusion Principle,no two electrons in an atom can have the same set of all four quantum numbers. For Helium ($He$,atomic number $Z = 2$),the electronic configuration is $1s^2$. The two electrons in the $1s$ orbital have the same principal quantum number $(n=1)$,azimuthal quantum number $(l=0)$,and magnetic quantum number $(m_l=0)$. Therefore,they must have different spin quantum numbers $(m_s)$ to satisfy the principle. Thus,the spins are $+1/2$ and $-1/2$.

What are the spins of the two electrons in $He$?

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