The orbital angular momentum of an electron i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The orbital angular momentum $(L)$ of an electron is given by the formula: $L = \sqrt{l(l+1)} \hbar$, where $l$ is the azimuthal quantum number an

Vedclass · Accepted Answer

$\sqrt{6} \hbar$

Vedclass · Answer

(D) The orbital angular momentum $(L)$ of an electron is given by the formula: $L = \sqrt{l(l+1)} \hbar$, where $l$ is the azimuthal quantum number and $\hbar = \frac{h}{2\pi}$.For a $d$ orbital, the value of the azimuthal quantum number $l$ is $2$.Substituting $l = 2$ into the formula:$L = \sqrt{2(2+1)} \hbar$$L = \sqrt{2(3)} \hbar$$L = \sqrt{6} \hbar$Therefore, the orbital angular momentum of an electron in a $d$ orbital is $\sqrt{6} \hbar$.

The orbital angular momentum of an electron in a $d$ orbital is equal to:

Similar Questions

For the configuration shown in the image,which rule is violated $:-$

The electronic configuration of fluorine is

The correct set of four quantum numbers for the valence electron of rubidium $(Z = 37)$ is:

How many radial nodes are present in $4s$ and $3s$ orbitals respectively?

What are the four quantum numbers for the valence electron of sodium $(Z = 11)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module