Identify the odd-electron molecules among NO, | vedclass

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Question

(B) To identify odd-electron molecules,we calculate the total number of valence electrons in each molecule:$1$. $NO$: Valence electrons = $5 (N) + 6 (

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$NO$ and $NO_2$

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(B) To identify odd-electron molecules,we calculate the total number of valence electrons in each molecule:$1$. $NO$: Valence electrons = $5 (N) + 6 (O) = 11$. Since $11$ is an odd number,$NO$ is an odd-electron molecule.$2$. $NO_2$: Valence electrons = $5 (N) + 2 	imes 6 (O) = 17$. Since $17$ is an odd number,$NO_2$ is an odd-electron molecule.$3$. $CO$: Valence electrons = $4 (C) + 6 (O) = 10$. Since $10$ is an even number,$CO$ is not an odd-electron molecule.$4$. $CO_2$: Valence electrons = $4 (C) + 2 	imes 6 (O) = 16$. Since $16$ is an even number,$CO_2$ is not an odd-electron molecule.Therefore,$NO$ and $NO_2$ are odd-electron molecules.

Identify the odd-electron molecules among $NO$,$NO_2$,$CO$,and $CO_2$. Explain why.

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