How is the hybridization of an atom determined as $sp$,$sp^2$,or $sp^3$?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The hybridization of an atom is determined by the bond angle and the molecular geometry.
$1.$ If the bond angle is $180^{\circ}$ and the geometry is linear,the hybridization is $sp$.
$2.$ If the bond angle is $120^{\circ}$ and the geometry is trigonal planar,the hybridization is $sp^2$.
$3.$ If the bond angle is $109.5^{\circ}$ and the geometry is tetrahedral,the hybridization is $sp^3$.

Explore More

Similar Questions

What type of covalent bond is formed by hybrid orbitals?

$C-H$ bond length is least in

Explain the tetrahedral structure of $CH_4$ (methane) using its bonding structure.

Difficult
View Solution

Which of the following compounds has $sp^2$ hybridization?

The species in which the central atom uses $sp^2$ hybrid orbitals in its bonding is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo