The ionization constant of ammonium hydroxide at $298 \ K$ is $1.77 \times 10^{-5}$. Calculate the hydrolysis constant of ammonium chloride.
- A$5.65 \times 10^{-10}$
- B$6.50 \times 10^{-10}$
- C$5.65 \times 10^{-5}$
- D$1.77 \times 10^{-9}$
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