$H_2S$ gas,when passed through a solution containing $HCl$,precipitates the cations of group $II$ of qualitative analysis but not those belonging to the fourth group. This is because:

  • A
    Presence of $HCl$ decreases the sulphide ion concentration
  • B
    Presence of $HCl$ increases the sulphide ion concentration
  • C
    Solubility product of group $II$ sulphides is more than that of group $IV$ sulphides
  • D
    Sulphides of group $IV$ cations are soluble in $HCl$

Explore More

Similar Questions

The ionization constant of phenol is $1.0 \times 10^{-10}.$ What is the concentration of phenolate ion in $0.05 \ M$ solution of phenol? What will be its degree of ionization if the solution is also $0.01 \ M$ in sodium phenolate?

Difficult
View Solution

Why is pure $NaCl$ precipitated when $HCl$ gas is passed through a saturated solution of $NaCl$?

Difficult
View Solution

On passing $H_2S$ gas through a highly acidic solution containing $Cd^{2+}$ ions,$CdS$ is not precipitated because

Calculate $[S^{2-}]$ and $[HS^{-}]$ of the solution which contains $0.1 \ M \ H_2S$ and $0.3 \ M \ HCl$.
[$K_{a1} = 1.0 \times 10^{-7}$ and $K_{a2} = 1.3 \times 10^{-13}$ for $H_2S$]

Difficult
View Solution

Aqueous ammonia is used instead of an aqueous solution of $NaOH$ to precipitate $Al^{+3}$ ions as $Al(OH)_3$ because:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo