Match the reactants in Column-$(I)$ with the products formed in Column-$(II)$.
Column-$(I)$ (Reactants)Column-$(II)$ (Major Products)
$(A)$ $C_6H_5CH_3 + X_2 \xrightarrow{Fe, \text{dark}}$$(i)$ $C_6H_5CH(Br)CH_3$
$(B)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 \ K}$$(ii)$ $C_6H_5N_2^+X^-$
$(C)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2}$$(iii)$ $p-X-C_6H_4CH_3 + o-X-C_6H_4CH_3$
$(D)$ $C_6H_5CH_2CH_3 \xrightarrow{Br_2, \Delta \text{ or } UV \text{ light}}$$(iv)$ $C_6H_5X$

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(A-III, B-II, C-IV, D-I) $(A \rightarrow iii)$: Electrophilic aromatic substitution of toluene with $X_2$ in the presence of $Fe$ (dark) gives ortho and para halo-substituted toluene.
$(B \rightarrow ii)$: Aniline reacts with $NaNO_2$ and $HX$ at $273-278 \ K$ to form benzene diazonium salt.
$(C \rightarrow iv)$: Sandmeyer reaction of benzene diazonium salt with $Cu_2X_2$ yields aryl halide $(C_6H_5X)$.
$(D \rightarrow i)$: Free radical bromination of ethylbenzene with $Br_2$ under light/heat occurs at the benzylic position to form $1$-bromo-$1$-phenylethane.

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Correct statements regarding alkyl halides ($R-X$) among the following are: A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$. B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$. C. Non substituted aryl halides exhibit properties similar to alkyl halides. D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne. E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$. Choose the correct answer from the options given below:

Match the reactions in Column-$I$ with their mechanisms in Column-$II$.
Column-$I$ (Reaction) Column-$II$ (Mechanism)
$(A)$ $OH^- + CH_3Cl \to HOCH_3 + Cl^-$ $(1)$ $S_N2$ mechanism
$(B)$ $(CH_3)_3CBr + OH^- \to (CH_3)_3COH + Br^-$ $(2)$ $S_E2$ aromatic
$(C)$ $CH_3CH_2Br \xrightarrow[ethanol]{KOH} CH_2 = CH_2$ $(3)$ $S_N1$ mechanism
$(D)$ $C_6H_6 + Br_2 \xrightarrow{Fe} C_6H_5Br + HBr$ $(4)$ $\beta$-elimination (dehydrohalogenation)

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Consider the following sequence of reactions:
Nitrobenzene $\xrightarrow[(ii) NaNO_2, HCl, 0^{\circ}C]{(i) Sn + HCl} \text{Benzenediazonium chloride}$ $\xrightarrow{(iii) Cu_2Cl_2} \text{Chlorobenzene}$ $\xrightarrow{(iv) Na, \text{Ether}} A$
Molar mass of the product formed $(A)$ is $.............. \ g \ mol^{-1}$.

Arrange the following reactants in increasing order of reactivity towards $S_{N^1}$ solvolysis reaction with methanol.

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Identify the major products $(P)$ and $(Q)$ respectively for the given reaction.

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