A and B together have ₹ 6300. If frac{5}{19} | vedclass

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Question

(A) Let the amount with $A$ be $A$ and the amount with $B$ be $B$.Given that $A + B = 6300$.According to the problem,$\frac{5}{19} A = \frac{2}{5} B$.

Vedclass · Accepted Answer

$2500$

Vedclass · Answer

(A) Let the amount with $A$ be $A$ and the amount with $B$ be $B$.Given that $A + B = 6300$.According to the problem,$\frac{5}{19} A = \frac{2}{5} B$.Cross-multiplying,we get $25 A = 38 B$,which implies $\frac{A}{B} = \frac{38}{25}$.Let $A = 38x$ and $B = 25x$.Substituting these into the sum: $38x + 25x = 6300$.$63x = 6300$,which gives $x = 100$.Therefore,the amount of $B = 25x = 25 	imes 100 = 2500$.Wait,re-evaluating the ratio: $\frac{5}{19} A = \frac{2}{5} B \Rightarrow A/B = (2/5) 	imes (19/5) = 38/25$. The sum is $38x + 25x = 63x = 6300 \Rightarrow x = 100$. So $B = 25 	imes 100 = 2500$.

$A$ and $B$ together have ₹ $6300$. If $\frac{5}{19}$ of $A$'s amount is equal to $\frac{2}{5}$ of $B$'s amount,then the amount of $B$ is (in ₹):

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