A, B and C can do a piece of work individuall | vedclass

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(A) Work done by $A$ and $B$ in $1$ day $= \frac{1}{8} + \frac{1}{12} = \frac{3+2}{24} = \frac{5}{24}$.Work done by $A$ and $B$ in $2$ days $= 2 	ime

Vedclass · Accepted Answer

$5 \frac{8}{9}$

Vedclass · Answer

(A) Work done by $A$ and $B$ in $1$ day $= \frac{1}{8} + \frac{1}{12} = \frac{3+2}{24} = \frac{5}{24}$.Work done by $A$ and $B$ in $2$ days $= 2 	imes \frac{5}{24} = \frac{10}{24} = \frac{5}{12}$.Remaining work $= 1 - \frac{5}{12} = \frac{7}{12}$.One day work of $B$ and $C$ together $= \frac{1}{12} + \frac{1}{15} = \frac{5+4}{60} = \frac{9}{60} = \frac{3}{20}$.Days required by $B$ and $C$ to finish the remaining work $= \frac{7/12}{3/20} = \frac{7}{12} 	imes \frac{20}{3} = \frac{7 	imes 5}{3 	imes 3} = \frac{35}{9}$ days.Total days to complete the work $= 2 + \frac{35}{9} = \frac{18+35}{9} = \frac{53}{9} = 5 \frac{8}{9}$ days.

$A, B$ and $C$ can do a piece of work individually in $8, 12$ and $15$ days,respectively. $A$ and $B$ start working,but $A$ quits after working for $2$ days. After this,$C$ joins $B$ until the completion of the work. In how many days will the work be completed?

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