A alone can do a piece of work in 6 days and | vedclass

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(B) Work done by $A$ in $1$ day $= \frac{1}{6}$.Work done by $B$ in $1$ day $= \frac{1}{8}$.Work done by $(A+B+C)$ in $1$ day $= \frac{1}{3}$.Work don

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(B) Work done by $A$ in $1$ day $= \frac{1}{6}$.Work done by $B$ in $1$ day $= \frac{1}{8}$.Work done by $(A+B+C)$ in $1$ day $= \frac{1}{3}$.Work done by $C$ in $1$ day $= 	ext{Work}(A+B+C) - 	ext{Work}(A+B) = \frac{1}{3} - (\frac{1}{6} + \frac{1}{8}) = \frac{1}{3} - (\frac{4+3}{24}) = \frac{1}{3} - \frac{7}{24} = \frac{8-7}{24} = \frac{1}{24}$.The ratio of work done by $A, B,$ and $C$ is $\frac{1}{6} : \frac{1}{8} : \frac{1}{24}$.Multiplying by $24$,the ratio is $4 : 3 : 1$.Total share $= 4+3+1 = 8$ units.Total amount $= Rs. 3200$.Share of $C = \frac{1}{8} 	imes 3200 = Rs. 400$.

$A$ alone can do a piece of work in $6$ days and $B$ alone in $8$ days. $A$ and $B$ undertook to do it for $Rs. 3200$. With the help of $C$,they completed the work in $3$ days. How much is to be paid to $C$ (in $Rs.$)?

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