P, Q and R can do a piece of work in 60 days, | vedclass

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Question

(C) The work done by $P, Q,$ and $R$ in one day is the reciprocal of the total days taken by each.$P$'s one-day work $= 1/60$$Q$'s one-day work $= 1/1

Vedclass · Accepted Answer

$960$

Vedclass · Answer

(C) The work done by $P, Q,$ and $R$ in one day is the reciprocal of the total days taken by each.$P$'s one-day work $= 1/60$$Q$'s one-day work $= 1/100$$R$'s one-day work $= 1/80$The ratio of their work efficiency is $1/60 : 1/100 : 1/80$.To simplify,find the $LCM$ of $60, 100,$ and $80$,which is $1200$.Multiplying by $1200$,we get the ratio: $(1200/60) : (1200/100) : (1200/80) = 20 : 12 : 15$.The sum of the ratio parts $= 20 + 12 + 15 = 47$.$P$'s share $= (20/47) 	imes 2256$.$2256 / 47 = 48$.$P$'s share $= 20 	imes 48 = 960$.Thus,$P$ will receive $Rs. 960$.

$P, Q$ and $R$ can do a piece of work in $60$ days,$100$ days and $80$ days respectively. They work together to finish the work and receive $Rs. 2256$. Then $P$ will get (in $Rs.$)

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