A can do frac{1}{3} of a work in 5 text{ days | vedclass

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(B) can do $\frac{1}{3}$ of the work in $5 	ext{ days}$. Therefore,$A$ can complete the whole work in $5 	imes 3 = 15 	ext{ days}$.$B$ can do $\fra

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$9 \frac{3}{8}$

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(B) can do $\frac{1}{3}$ of the work in $5 	ext{ days}$. Therefore,$A$ can complete the whole work in $5 	imes 3 = 15 	ext{ days}$.$B$ can do $\frac{2}{5}$ of the work in $10 	ext{ days}$. Therefore,$B$ can complete the whole work in $10 	imes \frac{5}{2} = 25 	ext{ days}$.Let $X = 15$ and $Y = 25$.The time taken by $A$ and $B$ working together to complete the work is given by the formula $\frac{X 	imes Y}{X + Y}$.Substituting the values: $\frac{15 	imes 25}{15 + 25} = \frac{375}{40} = \frac{75}{8} 	ext{ days}$.Converting to a mixed fraction: $\frac{75}{8} = 9 \frac{3}{8} 	ext{ days}$.

$A$ can do $\frac{1}{3}$ of a work in $5 \text{ days}$ and $B$ can do $\frac{2}{5}$ of the work in $10 \text{ days}$. In how many $\text{days}$ can both $A$ and $B$ together do the work?

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