A and B can do a piece of work in 8 days,B an | vedclass

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(C) Let the total work be the Least Common Multiple $(LCM)$ of $8, 12,$ and $6$,which is $24$ units.Efficiency of $(A+B) = 24 / 8 = 3$ units/day.Effic

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$8$

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(C) Let the total work be the Least Common Multiple $(LCM)$ of $8, 12,$ and $6$,which is $24$ units.Efficiency of $(A+B) = 24 / 8 = 3$ units/day.Efficiency of $(B+C) = 24 / 12 = 2$ units/day.Efficiency of $(A+B+C) = 24 / 6 = 4$ units/day.To find the efficiency of $B$,we use the equation: $(A+B) + (B+C) - (A+B+C) = B$.Efficiency of $B = 3 + 2 - 4 = 1$ unit/day.Now,find the efficiency of $(A+C)$:Efficiency of $(A+C) = (A+B+C) - B = 4 - 1 = 3$ units/day.Time taken by $A$ and $C$ to complete the work = Total work / Efficiency of $(A+C) = 24 / 3 = 8$ days.

$A$ and $B$ can do a piece of work in $8$ days,$B$ and $C$ can do the same work in $12$ days,and $A, B,$ and $C$ together complete it in $6$ days. The number of days required to finish the work by $A$ and $C$ together is:

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