A and B can do a piece of work in 45 days and | vedclass

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(C) Work done by $A$ in $1$ day $= \frac{1}{45}$.Work done by $B$ in $1$ day $= \frac{1}{40}$.Let $A$ work for $x$ days. Both $A$ and $B$ worked toget

Vedclass · Accepted Answer

$9$

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(C) Work done by $A$ in $1$ day $= \frac{1}{45}$.Work done by $B$ in $1$ day $= \frac{1}{40}$.Let $A$ work for $x$ days. Both $A$ and $B$ worked together for $x$ days.$B$ worked alone for $23$ days.Total work done $= 1$.Equation: $x \left( \frac{1}{45} + \frac{1}{40} ight) + 23 \left( \frac{1}{40} ight) = 1$.$x \left( \frac{8 + 9}{360} ight) + \frac{23}{40} = 1$.$x \left( \frac{17}{360} ight) = 1 - \frac{23}{40} = \frac{17}{40}$.$x = \frac{17}{40} 	imes \frac{360}{17} = 9$ days.Thus,$A$ left the work after $9$ days.

$A$ and $B$ can do a piece of work in $45$ days and $40$ days respectively. They began to do the work together,but $A$ leaves after some days and then $B$ completed the remaining work in $23$ days. The number of days after which $A$ left the work was:

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