Delta ABC is similar to Delta PQR. The length | vedclass

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(C) According to the property of similar triangles,the ratio of the areas of two similar triangles is equal to the square of the ratio of their corres

Vedclass · Accepted Answer

$324$

Vedclass · Answer

(C) According to the property of similar triangles,the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.$\frac{	ext{Area}(\Delta ABC)}{	ext{Area}(\Delta PQR)} = \frac{AB^2}{PQ^2}$Given that $	ext{Area}(\Delta ABC) = 1024 \ cm^2$,$AB = 16 \ cm$,and $PQ = 9 \ cm$:$\frac{1024}{	ext{Area}(\Delta PQR)} = \frac{16^2}{9^2}$$\frac{1024}{	ext{Area}(\Delta PQR)} = \frac{256}{81}$$	ext{Area}(\Delta PQR) = \frac{1024 	imes 81}{256}$$	ext{Area}(\Delta PQR) = 4 	imes 81 = 324 \ cm^2$.

$\Delta ABC$ is similar to $\Delta PQR$. The length of $AB$ is $16 \ cm$ and the length of the corresponding side $PQ$ is $9 \ cm$. If the area of $\Delta ABC$ is $1024 \ cm^2$,what is the area of $\Delta PQR$ in $cm^2$?

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