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(C) Let the length of the rectangle be $L$ and its width be $B$. The original perimeter is $P_1 = 2(L + B)$.When the sides are increased by $20 \%$,th

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$20$

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(C) Let the length of the rectangle be $L$ and its width be $B$. The original perimeter is $P_1 = 2(L + B)$.When the sides are increased by $20 \%$,the new length becomes $L' = L + 0.2L = 1.2L$ and the new width becomes $B' = B + 0.2B = 1.2B$.The new perimeter is $P_2 = 2(L' + B') = 2(1.2L + 1.2B)$.Simplifying this,we get $P_2 = 2 	imes 1.2(L + B) = 2.4(L + B)$.The increase in perimeter is $\Delta P = P_2 - P_1 = 2.4(L + B) - 2(L + B) = 0.4(L + B)$.The percentage increase in perimeter is $\frac{\Delta P}{P_1} 	imes 100 = \frac{0.4(L + B)}{2(L + B)} 	imes 100 = 0.2 	imes 100 = 20 \%$.

If the sides of a rectangle are increased by $20 \%$,the percentage increase in its perimeter is

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