A circular wire of diameter 112 , cm is cut a | vedclass

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(C) The circumference of the circular wire is equal to the perimeter of the rectangle.Given diameter $d = 112 \, cm$.Circumference of circle $= \pi

Vedclass · Accepted Answer

$77$

Vedclass · Answer

(C) The circumference of the circular wire is equal to the perimeter of the rectangle.Given diameter $d = 112 \, cm$.Circumference of circle $= \pi 	imes d = \frac{22}{7} 	imes 112 = 22 	imes 16 = 352 \, cm$.Let the sides of the rectangle be $9x$ and $7x$.The perimeter of the rectangle $= 2 	imes (9x + 7x) = 2 	imes 16x = 32x$.Equating the perimeters: $32x = 352$.$x = \frac{352}{32} = 11$.The smaller side of the rectangle is $7x = 7 	imes 11 = 77 \, cm$.

$A$ circular wire of diameter $112 \, cm$ is cut and bent in the form of a rectangle whose sides are in the ratio of $9:7$. The small side of the rectangle is......$cm$.

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