The perimeter of a rhombus is 60 , cm and one | vedclass

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(B) The perimeter of a rhombus is given by $P = 4 	imes 	ext{side}$.Since the perimeter is $60 \, cm$, the side length $a = 60 / 4 = 15 \, cm$.In a

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$216$

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(B) The perimeter of a rhombus is given by $P = 4 	imes 	ext{side}$.Since the perimeter is $60 \, cm$, the side length $a = 60 / 4 = 15 \, cm$.In a rhombus, the diagonals bisect each other at right angles. Let the diagonals be $d_1 = 24 \, cm$ and $d_2$. Half of the diagonals are $d_1/2 = 12 \, cm$ and $d_2/2$.Using the Pythagorean theorem in one of the four right-angled triangles formed by the diagonals: $(d_1/2)^2 + (d_2/2)^2 = a^2$.$12^2 + (d_2/2)^2 = 15^2$.$144 + (d_2/2)^2 = 225$.$(d_2/2)^2 = 225 - 144 = 81$.$d_2/2 = 9 \, cm$, so $d_2 = 18 \, cm$.The area of a rhombus is given by $	ext{Area} = (1/2) 	imes d_1 	imes d_2$.$	ext{Area} = (1/2) 	imes 24 	imes 18 = 12 	imes 18 = 216 \, cm^2$.

The perimeter of a rhombus is $60 \, cm$ and one of its diagonals is $24 \, cm$. The area (in $sq. cm$) of the rhombus is

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