A man runs round a circular field of radius 5 | vedclass

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(B) The circumference of the circular field is given by $C = 2 \pi r = 2 \pi 	imes 50 = 100 \pi\, m$.For $20$ rounds, the total distance to be covere

Vedclass · Accepted Answer

$32$

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(B) The circumference of the circular field is given by $C = 2 \pi r = 2 \pi 	imes 50 = 100 \pi\, m$.For $20$ rounds, the total distance to be covered is $D = 20 	imes 100 \pi = 2000 \pi\, m$.The speed of the man is $12\, km/hr$. Converting this to $m/s$:$v = 12 	imes \frac{5}{18} = \frac{60}{18} = \frac{10}{3}\, m/s$.The time taken in seconds is $T = \frac{D}{v} = \frac{2000 \pi}{10/3} = 2000 \pi 	imes \frac{3}{10} = 600 \pi\, s$.Converting the time into minutes:$T_{min} = \frac{600 \pi}{60} = 10 \pi\, minutes$.Using $\pi \approx 3.14$, $T_{min} = 10 	imes 3.14 = 31.4\, minutes$.Rounding to the nearest integer, the time taken is approximately $32\, minutes$.

$A$ man runs round a circular field of radius $50\, m$ at the speed of $12\, km/hr$. What is the time taken by the man to take twenty rounds of the field? (in $minutes$)

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