A silver wire when bent in the form of a squa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The perimeter of the wire remains constant regardless of the shape.Let the side of the square be $a \, cm$.Given,area of the square $= a^{2} = 484

Vedclass · Accepted Answer

$616$

Vedclass · Answer

(C) The perimeter of the wire remains constant regardless of the shape.Let the side of the square be $a \, cm$.Given,area of the square $= a^{2} = 484 \, cm^{2}$.Therefore,$a = \sqrt{484} = 22 \, cm$.Perimeter of the square $= 4a = 4 	imes 22 = 88 \, cm$.Since the same wire is used to form a circle,the circumference of the circle is equal to the perimeter of the square.Let the radius of the circle be $r \, cm$.Circumference $= 2\pi r = 88 \, cm$.$2 	imes \frac{22}{7} 	imes r = 88$.$r = \frac{88 	imes 7}{44} = 14 \, cm$.Area of the circle $= \pi r^{2} = \frac{22}{7} 	imes 14 	imes 14 = 22 	imes 2 	imes 14 = 616 \, cm^{2}$.

$A$ silver wire when bent in the form of a square,encloses an area of $484 \, cm^{2}$. Now if the same wire is bent to form a circle,the area enclosed by the circle would be? (in $cm^{2}$)

Similar Questions

If the curved surface area of a cone is thrice that of another cone and the slant height of the second cone is thrice that of the first,find the ratio of the area of their bases. (in $:1$)

The area of a rectangular field is $27000 \, m^2$. The ratio of its length and breadth is $6:5$. The length and breadth of the field are respectively:

If the perimeter of an isosceles right triangle is $(6+3 \sqrt{2}) \text{ m}$,then the area of the triangle is ... $\text{m}^2$.

The length and breadth of a rectangular field are in the ratio $5: 3.$ If the cost of cultivating the field at $25$ $paise$ per square metre is ₹ $6000,$ then find the dimensions of the field.

$A$ wire is looped in the form of a circle of radius $28\, cm$. It is bent again into a square form. What will be the length of the diagonal of the largest square possible thus?

Vedclass Test Series

Exam Paper Generator

Online Exam Module