1+1 divleft{1+1 divleft(1-frac{1}{3}right)rig | vedclass

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Question

(A) To solve the expression $1+1 \div\left\{1+1 \div\left(1-\frac{1}{3}\right)\right\}$,we follow the $BODMAS$ rule.First,solve the innermost bracket:

Vedclass · Accepted Answer

$\frac{7}{5}$

Vedclass · Answer

(A) To solve the expression $1+1 \div\left\{1+1 \div\left(1-\frac{1}{3}ight)ight\}$,we follow the $BODMAS$ rule.First,solve the innermost bracket: $(1-\frac{1}{3}) = \frac{2}{3}$.The expression becomes $1+1 \div\left\{1+1 \div \frac{2}{3}ight\}$.Next,perform the division inside the curly bracket: $1 \div \frac{2}{3} = 1 	imes \frac{3}{2} = \frac{3}{2}$.The expression becomes $1+1 \div\left\{1+\frac{3}{2}ight\}$.Simplify the curly bracket: $1+\frac{3}{2} = \frac{2+3}{2} = \frac{5}{2}$.The expression becomes $1+1 \div \frac{5}{2}$.Finally,perform the division: $1+1 	imes \frac{2}{5} = 1+\frac{2}{5} = \frac{7}{5}$.

$1+1 \div\left\{1+1 \div\left(1-\frac{1}{3}\right)\right\}=?$

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