1 . overline{27} in the form frac{p}{q} is eq | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $x = 1 . \overline{27} = 1.272727...$ (Equation $1$)Multiply both sides by $100$ since two digits are repeating:$100x = 127.272727...$ (Equati

Vedclass · Accepted Answer

$\frac{14}{11}$

Vedclass · Answer

(C) Let $x = 1 . \overline{27} = 1.272727...$ (Equation $1$)Multiply both sides by $100$ since two digits are repeating:$100x = 127.272727...$ (Equation $2$)Subtract Equation $1$ from Equation $2$:$100x - x = 127.272727... - 1.272727...$$99x = 126$$x = \frac{126}{99}$Divide both numerator and denominator by $9$:$x = \frac{14}{11}$

$1 . \overline{27}$ in the form $\frac{p}{q}$ is equal to

Similar Questions

Write down the following quotients in descending order:
$1.$ $\frac{368.39}{17}$
$2.$ $\frac{170.50}{62}$
$3.$ $\frac{875.65}{83}$

$3 \frac{1}{4} + 2 \frac{1}{2} - 1 \frac{5}{6} = \frac{(?)^{2}}{10} + 1 \frac{5}{12}$

$\frac{0.009}{?} = 0.01$

If $x=\sqrt[3]{5}+2,$ then the value of $x^{3}-6 x^{2}+12 x-13$ is

$\frac{3}{8}$ of $168 \times 15 \div 5 + ? = 549 \div 9 + 235$

Vedclass Test Series

Exam Paper Generator

Online Exam Module