sqrt{80} + 3sqrt{245} - sqrt{125} = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,simplify each square root term by finding the prime factors:$\sqrt{80} = \sqrt{16 	imes 5} = 4\sqrt{5}$$3\sqrt{245} = 3\sqrt{49 	imes 5} =

Vedclass · Accepted Answer

$20\sqrt{5}$

Vedclass · Answer

(A) First,simplify each square root term by finding the prime factors:$\sqrt{80} = \sqrt{16 	imes 5} = 4\sqrt{5}$$3\sqrt{245} = 3\sqrt{49 	imes 5} = 3 	imes 7\sqrt{5} = 21\sqrt{5}$$\sqrt{125} = \sqrt{25 	imes 5} = 5\sqrt{5}$Now,substitute these values back into the expression:$4\sqrt{5} + 21\sqrt{5} - 5\sqrt{5}$$= (4 + 21 - 5)\sqrt{5}$$= 20\sqrt{5}$

$\sqrt{80} + 3\sqrt{245} - \sqrt{125} = ?$

Similar Questions

$\sqrt{1.5625} = ?$

Given $\sqrt{2} = 1.414$. The value of $\sqrt{8} + 2\sqrt{32} - 3\sqrt{128} + 4\sqrt{50}$ is

The value of $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$ is

$\sqrt{10} \times \sqrt{15} = ?$

$[(3 \sqrt{8} + \sqrt{8}) \times (8 \sqrt{8} + 7 \sqrt{8})] - 98 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module