frac{sqrt{1296}}{?} = frac{?}{2.25} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the missing number be $x$.Then,the equation is $\frac{\sqrt{1296}}{x} = \frac{x}{2.25}$.We know that $\sqrt{1296} = 36$.Substituting this valu

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) Let the missing number be $x$.Then,the equation is $\frac{\sqrt{1296}}{x} = \frac{x}{2.25}$.We know that $\sqrt{1296} = 36$.Substituting this value,we get $\frac{36}{x} = \frac{x}{2.25}$.Cross-multiplying,we get $x^2 = 36 	imes 2.25$.$x^2 = 36 	imes \frac{225}{100}$.Taking the square root on both sides,$x = \sqrt{36 	imes \frac{225}{100}}$.$x = 6 	imes \frac{15}{10} = 6 	imes 1.5 = 9$.Therefore,the missing number is $9$.

$\frac{\sqrt{1296}}{?} = \frac{?}{2.25}$

Similar Questions

If $\sqrt{x} + \sqrt{441} = 0.02$,then the value of $x$ is

The value of $\sqrt{0.000441}$ is

$\frac{\sqrt{0.0009}}{\sqrt{0.01}} = ?$

If $\sqrt{12} = 3.464$,the value of $\sqrt{\frac{3}{4}} + 2 \sqrt{\frac{4}{3}}$ is

The value of $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module