If sqrt{12} = 3.464,the value of sqrt{frac{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $\sqrt{12} = 3.464$.We need to evaluate $\sqrt{\frac{3}{4}} + 2 \sqrt{\frac{4}{3}}$.Simplify the terms:$\sqrt{\frac{3}{4}} = \frac{\sqrt{3}

Vedclass · Accepted Answer

$3.1753$

Vedclass · Answer

(C) Given: $\sqrt{12} = 3.464$.We need to evaluate $\sqrt{\frac{3}{4}} + 2 \sqrt{\frac{4}{3}}$.Simplify the terms:$\sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{2} = \frac{\sqrt{3} 	imes 2}{2 	imes 2} = \frac{\sqrt{12}}{4}$.$2 \sqrt{\frac{4}{3}} = 2 	imes \frac{2}{\sqrt{3}} = \frac{4}{\sqrt{3}} = \frac{4 	imes \sqrt{3}}{3} = \frac{4 	imes \sqrt{3} 	imes 4}{3 	imes 4} = \frac{16 \sqrt{3}}{12} = \frac{8 \sqrt{12}}{12} = \frac{2 \sqrt{12}}{3}$.Adding them together:$\frac{\sqrt{12}}{4} + \frac{2 \sqrt{12}}{3} = \sqrt{12} \left( \frac{1}{4} + \frac{2}{3} ight) = \sqrt{12} \left( \frac{3 + 8}{12} ight) = \sqrt{12} \left( \frac{11}{12} ight)$.Substitute $\sqrt{12} = 3.464$:$= 3.464 	imes \frac{11}{12} = \frac{38.104}{12} = 3.175333... \approx 3.1753$.

If $\sqrt{12} = 3.464$,the value of $\sqrt{\frac{3}{4}} + 2 \sqrt{\frac{4}{3}}$ is

Similar Questions

The value of $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$ is

$1.5^{2} \times \sqrt{0.0225} = ?$

The square root of $\frac{(0.75)^{3}}{1-0.75}+\left(0.75+(0.75)^{2}+1\right)$ is

The value of $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$ is

By what least number should $2450$ be multiplied so that the resulting number is a perfect square?

Vedclass Test Series

Exam Paper Generator

Online Exam Module