sqrt{11449} times sqrt{6241} - (54)^{2} = sqr | vedclass

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Question

(B) First,calculate the square roots:$\sqrt{11449} = 107$$\sqrt{6241} = 79$Next,calculate the squares:$(54)^{2} = 2916$$(74)^{2} = 5476$Substitute the

Vedclass · Accepted Answer

$3721$

Vedclass · Answer

(B) First,calculate the square roots:$\sqrt{11449} = 107$$\sqrt{6241} = 79$Next,calculate the squares:$(54)^{2} = 2916$$(74)^{2} = 5476$Substitute these values into the equation:$107 	imes 79 - 2916 = \sqrt{?} + 5476$$8453 - 2916 = \sqrt{?} + 5476$$5537 = \sqrt{?} + 5476$Isolate $\sqrt{?}$:$\sqrt{?} = 5537 - 5476$$\sqrt{?} = 61$Finally,square both sides to find $?$:$? = (61)^{2} = 3721$

$\sqrt{11449} \times \sqrt{6241} - (54)^{2} = \sqrt{?} + (74)^{2}$

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