(D) $1$. Decarboxylation of sodium acetate: $CH_3COONa + NaOH \xrightarrow{CaO} CH_4 + Na_2CO_3$ $2$. Reduction of iodomethane: $CH_3I + 2[H] \xrighta

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(D) $1$. Decarboxylation of sodium acetate: $CH_3COONa + NaOH \xrightarrow{CaO} CH_4 + Na_2CO_3$ $2$. Reduction of iodomethane: $CH_3I + 2[H] \xrightarrow{Zn/HCl} CH_4 + HI$ $3$. Hydrolysis of aluminium carbide: $Al_4C_3 + 12H_2O \to 3CH_4 + 4Al(OH)_3$ Since all three reactions produce $CH_4$,the correct option is $D$.