57 frac{4}{7} + 29 frac{1}{21} + ? = 90 frac{ | vedclass

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Question

(D) Given the equation: $57 \frac{4}{7} + 29 \frac{1}{21} + ? = 90 \frac{3}{35}$Isolate the unknown term '$?$':$? = 90 \frac{3}{35} - 57 \frac{4}{7} -

Vedclass · Accepted Answer

$3 \frac{7}{15}$

Vedclass · Answer

(D) Given the equation: $57 \frac{4}{7} + 29 \frac{1}{21} + ? = 90 \frac{3}{35}$Isolate the unknown term '$?$':$? = 90 \frac{3}{35} - 57 \frac{4}{7} - 29 \frac{1}{21}$Separate the whole numbers and fractions:$? = (90 - 57 - 29) + (\frac{3}{35} - \frac{4}{7} - \frac{1}{21})$Calculate the whole number part:$90 - 57 - 29 = 4$Find a common denominator for the fractions $(35, 7, 21)$,which is $105$:$\frac{3}{35} = \frac{3 	imes 3}{105} = \frac{9}{105}$$\frac{4}{7} = \frac{4 	imes 15}{105} = \frac{60}{105}$$\frac{1}{21} = \frac{1 	imes 5}{105} = \frac{5}{105}$Combine the fractions:$\frac{9}{105} - \frac{60}{105} - \frac{5}{105} = \frac{9 - 65}{105} = -\frac{56}{105}$Simplify the expression:$? = 4 - \frac{56}{105} = 3 + (1 - \frac{56}{105}) = 3 + \frac{105 - 56}{105} = 3 + \frac{49}{105}$Reduce the fraction $\frac{49}{105}$ by dividing by $7$:$\frac{49 \div 7}{105 \div 7} = \frac{7}{15}$Thus,$? = 3 \frac{7}{15}$.

$57 \frac{4}{7} + 29 \frac{1}{21} + ? = 90 \frac{3}{35}$

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