40.83 times 1.02 times 1.2 = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To solve the expression $40.83 	imes 1.02 	imes 1.2$,we first multiply the numbers as if they were integers:$4083 	imes 102 	imes 12 = 4997592

Vedclass · Accepted Answer

$49.97592$

Vedclass · Answer

(C) To solve the expression $40.83 	imes 1.02 	imes 1.2$,we first multiply the numbers as if they were integers:$4083 	imes 102 	imes 12 = 4997592$Next,we count the total number of decimal places in the original expression:$40.83$ has $2$ decimal places.$1.02$ has $2$ decimal places.$1.2$ has $1$ decimal place.Total decimal places = $2 + 2 + 1 = 5$.Now,place the decimal point in the product $4997592$ such that there are $5$ digits to the right of the decimal point:$49.97592$

$40.83 \times 1.02 \times 1.2 = ?$

Similar Questions

If $(\sqrt{3}+1)^{2}=x+\sqrt{3} y,$ then the value of $(x+y)$ is

$13 \frac{4}{?} + 5 \frac{3}{4} \text{ of } 3 \frac{1}{5} \div 4 \frac{3}{5} = 17 \frac{4}{5}$

If $\sqrt{2^{n}} = 64$,then find the value of $n$.

If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The original fraction is

If $p=99,$ then the value of $p(p^{2}+3p+3)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module