I. x^{2}-20 x+91=0II. y^{2}-32 y+247=0 | vedclass

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(D) For equation $I: x^{2}-20 x+91=0$Factorizing the quadratic equation: $x^{2}-13 x-7 x+91=0$$x(x-13)-7(x-13)=0$$(x-7)(x-13)=0$Thus,$x = 7$ or $x = 1

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$x \leq y$

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(D) For equation $I: x^{2}-20 x+91=0$Factorizing the quadratic equation: $x^{2}-13 x-7 x+91=0$$x(x-13)-7(x-13)=0$$(x-7)(x-13)=0$Thus,$x = 7$ or $x = 13$.For equation $II: y^{2}-32 y+247=0$Factorizing the quadratic equation: $y^{2}-19 y-13 y+247=0$$y(y-19)-13(y-19)=0$$(y-13)(y-19)=0$Thus,$y = 13$ or $y = 19$.Comparing the values:If $x=7$,then $x If $x=13$,then $x \leq y$ (since $y$ is $13$ or $19$).In both cases,$x \leq y$.

$I. x^{2}-20 x+91=0$
$II. y^{2}-32 y+247=0$

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$I. x^{2}-20 x+91=0$$II. y^{2}-32 y+247=0$