$A$ gaseous hypothetical chemical equation $2A \rightleftharpoons 4B + C$ is carried out in a closed vessel. The concentration of $B$ is found to increase by $5 \times 10^{-3} \ mol \ L^{-1}$ in $10 \ s$. The rate of appearance of $B$ is
- A$5 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
- B$5 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$
- C$6 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$
- D$4 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
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Similar Questions
The rate of disappearance of $MnO_4^-$ in the following reaction is $4.56 \times 10^{-3} \ M/s$.
$2MnO_4^- + 10I^{-} + 16H^{+} \to 2Mn^{2+} + 5I_2 + 8H_2O$
The rate of appearance of $I_2$ is:
$2MnO_4^- + 10I^{-} + 16H^{+} \to 2Mn^{2+} + 5I_2 + 8H_2O$
The rate of appearance of $I_2$ is:
Medium
View SolutionFor the reaction,$NO_{2(g)} + CO_{(g)} \rightarrow NO_{(g)} + CO_{2(g)}$,the rate of formation of $NO_{(g)}$ is $Y$ (in $mol \ dm^{-3} \ s^{-1}$). Find the rate of disappearance of $CO_{(g)}$ (in $mol \ dm^{-3} \ s^{-1}$)?
In a pseudo first order hydrolysis of ester in water,the following results were obtained:
$t \ (s)$ $0$ $30$ $60$ $90$ $[\text{Ester}] \ (mol \ L^{-1})$ $0.55$ $0.31$ $0.17$ $0.085$
What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?
| $t \ (s)$ | $0$ | $30$ | $60$ | $90$ |
| $[\text{Ester}] \ (mol \ L^{-1})$ | $0.55$ | $0.31$ | $0.17$ | $0.085$ |
What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?
Medium
View SolutionWrite the rate equation for the following reactions:
$1.$ $2 N_2 O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$
$2.$ $2 HI_{(g)} \rightarrow H_{2(g)} + I_{2(g)}$
$1.$ $2 N_2 O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$
$2.$ $2 HI_{(g)} \rightarrow H_{2(g)} + I_{2(g)}$
Medium
View SolutionFor the chemical reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$,the rate of reaction can be expressed in terms of the concentration of $N_{2(g)}$,$H_{2(g)}$,or $NH_{3(g)}$ with respect to time. Identify the correct relationship between these rates.
Medium
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