If Delta ABC sim Delta DEF for the correspond | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Since $\Delta ABC \sim \Delta DEF$,the ratios of their corresponding sides are equal:$\frac{AB}{DE} = \frac{AC}{DF} = \frac{BC}{EF} = k$Given $AB

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) Since $\Delta ABC \sim \Delta DEF$,the ratios of their corresponding sides are equal:$\frac{AB}{DE} = \frac{AC}{DF} = \frac{BC}{EF} = k$Given $AB = 8$,$DE = 12$,$AC = 10$,and $EF = 18$.The ratio of similarity $k = \frac{AB}{DE} = \frac{8}{12} = \frac{2}{3}$.Now,find the remaining sides of $\Delta DEF$:$\frac{AC}{DF} = \frac{2}{3} \implies \frac{10}{DF} = \frac{2}{3} \implies DF = \frac{10 	imes 3}{2} = 15$.$\frac{BC}{EF} = \frac{2}{3} \implies \frac{BC}{18} = \frac{2}{3} \implies BC = \frac{18 	imes 2}{3} = 12$.Now,find the perimeter of $\Delta DEF = DE + EF + DF = 12 + 18 + 15 = 45$.

If $\Delta ABC \sim \Delta DEF$ for the correspondence $ABC \leftrightarrow DEF$,and given $AB = 8$,$AC = 10$,$DE = 12$,and $EF = 18$,find the perimeter of $\Delta DEF$.

Similar Questions

The areas of two similar triangles are $9$ and $16$. Then,the ratio of their corresponding sides is...............

In the given figure,$\angle BAC = 90^{\circ}$ and $AD \perp BC$. Then,

Given $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$. If $AB : XY = 4 : 5$ and $YZ = 20$,find $BC$.

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $\overline{BM}$ is an altitude to the hypotenuse $\overline{AC}$. Then,$\angle BAM \cong \ldots$

In the figure,two chords $AB$ and $CD$ intersect each other at the point $P$. Prove that $\Delta APC \sim \Delta DPB$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module