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Question

(B) Two angles are supplementary if their sum is $180^{\circ}$.Therefore,$\angle A + \angle B = 180^{\circ}$.Substituting the given expressions: $(3x

Vedclass · Accepted Answer

$\angle A = 86^{\circ}, \angle B = 94^{\circ}$

Vedclass · Answer

(B) Two angles are supplementary if their sum is $180^{\circ}$.Therefore,$\angle A + \angle B = 180^{\circ}$.Substituting the given expressions: $(3x - 10^{\circ}) + (2x + 30^{\circ}) = 180^{\circ}$.Combining like terms: $5x + 20^{\circ} = 180^{\circ}$.Subtracting $20^{\circ}$ from both sides: $5x = 160^{\circ}$.Dividing by $5$: $x = 32^{\circ}$.Now,calculate $\angle A$: $\angle A = 3(32^{\circ}) - 10^{\circ} = 96^{\circ} - 10^{\circ} = 86^{\circ}$.Calculate $\angle B$: $\angle B = 2(32^{\circ}) + 30^{\circ} = 64^{\circ} + 30^{\circ} = 94^{\circ}$.Thus,$\angle A = 86^{\circ}$ and $\angle B = 94^{\circ}$.

$\angle A$ and $\angle B$ are supplementary angles. If $\angle A = 3x - 10^{\circ}$ and $\angle B = 2x + 30^{\circ}$,then find $\angle A$ and $\angle B$.

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