$\angle ACD$ is an exterior angle of $\Delta ABC$. If $\angle ACD = 122^{\circ}$ and $\angle A = 68^{\circ}$,then $\angle B = \ldots$ (in $^{\circ}$)

In $\Delta PQR$,$PQ = PR$. Prove that $\angle R = \angle Q$.

In the figure,$PQ > PR$ and $QS$ and $RS$ are the bisectors of $\angle Q$ and $\angle R$,respectively. Show that $SQ > SR$.

$M$ is a point on side $BC$ of a triangle $ABC$ such that $AM$ is the bisector of $\angle BAC$. Is it true to say that the perimeter of the triangle is greater than $2\, AM$? Give reason for your answer.

Write the measures of its sides in ascending order in each of the following triangles:
$(1) \text{In } \Delta ABC, \angle A = 50^{\circ} \text{ and } \angle B = 60^{\circ}$

In $\Delta PQR$,$PM$ is a median. If $\text{ar}(\Delta PMQ) = 36 \text{ cm}^2$,then find $\text{ar}(\Delta PMR)$ in $\text{cm}^2$.