ABCD is a square. If AC = 16 , cm,then find t | vedclass

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(B) Let the side of the square $ABCD$ be $a \, cm$.In a square,the diagonal $d$ is related to the side $a$ by the formula $d = a\sqrt{2}$.Given the di

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$128$

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(B) Let the side of the square $ABCD$ be $a \, cm$.In a square,the diagonal $d$ is related to the side $a$ by the formula $d = a\sqrt{2}$.Given the diagonal $AC = 16 \, cm$,we have $a\sqrt{2} = 16$.Squaring both sides,we get $2a^2 = 16^2 = 256$.Dividing by $2$,we find $a^2 = 128$.The area of a square is given by $a^2$.Therefore,the area of square $ABCD = 128 \, cm^2$.

$ABCD$ is a square. If $AC = 16 \, cm$,then find the area of $ABCD$ in $cm^2$.

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