$\frac{\cos ^{2} 40^{\circ}+\cos ^{2} 50^{\circ}}{\sin ^{2} 40^{\circ}+\sin ^{2} 50^{\circ}}=\ldots \ldots \ldots \ldots$

  • A
    $2$
  • B
    $4$
  • C
    $1$
  • D
    $0$

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Similar Questions

$\cot \theta \cdot \tan \theta = \dots$

જો $\sin A + \sin^2 A = 1$ હોય,તો $(\cos^2 A + \cos^4 A)$ પદાવલિનું મૂલ્ય કેટલું થાય?

Difficult
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પદાવલિ $\left[\frac{\sin ^{2} 22^{\circ}+\sin ^{2} 68^{\circ}}{\cos ^{2} 22^{\circ}+\cos ^{2} 68^{\circ}}+\sin ^{2} 63^{\circ}+\cos 63^{\circ} \sin 27^{\circ}\right]$ ની કિંમત શોધો.

Difficult
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સાબિત કરો કે $(\sin^{4} \theta - \cos^{4} \theta + 1) \operatorname{cosec}^{2} \theta = 2$.

જો $\sec 4A = \operatorname{cosec}(A - 20^{\circ})$ હોય,જ્યાં $4A$ એ લઘુકોણ છે,તો $A$ નું મૂલ્ય શોધો ($\circ$ માં).

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