A uniform rod of mass M and length L is place | vedclass

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(A) The motion of the centre of mass of a system of particles is governed by the net external force acting on the system,according to Newton's second

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$F/M$

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(A) The motion of the centre of mass of a system of particles is governed by the net external force acting on the system,according to Newton's second law: $F_{	ext{ext}} = M_{	ext{total}} \cdot a_{	ext{cm}}$.Here,the total mass of the rod is $M$ and the net external force applied is $F$.Therefore,the acceleration of the centre of mass is given by $a_{	ext{cm}} = \frac{F}{M}$.This acceleration is independent of the point of application of the force,as the centre of mass moves as if the entire mass were concentrated at that point and the force were acting directly on it.

$A$ uniform rod of mass $M$ and length $L$ is placed on a smooth horizontal surface. $A$ horizontal force $F$ is applied at one end of the rod perpendicular to its length. The acceleration of the centre of mass of the rod is:

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