(a) An ion M^{2+} contains 10 electrons and 1 | vedclass

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(A) An ion $M^{2+}$ is formed by the loss of $2$ electrons. Since the ion has $10$ electrons,the neutral atom $M$ must have $10 + 2 = 12$ electrons. I

Vedclass · Accepted Answer

$(a)$ Atomic number $= 12$,Mass number $= 24$

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(A) An ion $M^{2+}$ is formed by the loss of $2$ electrons. Since the ion has $10$ electrons,the neutral atom $M$ must have $10 + 2 = 12$ electrons. In a neutral atom,the number of electrons equals the number of protons,so the atomic number is $12$. The mass number is the sum of protons and neutrons: $12 + 12 = 24$.$(b)$ No,it is not possible. An atom is electrically neutral because the number of positively charged protons is equal to the number of negatively charged electrons. If an atom had $12$ protons and $13$ electrons,it would be an ion,not a neutral atom.$(c)$ Helium gas is inert because its outermost shell (the $K$ shell) is completely filled with $2$ electrons,making it stable and chemically unreactive.

$(a)$ An ion $M^{2+}$ contains $10$ electrons and $12$ neutrons. What is the atomic number and mass number of the element $M$?
$(b)$ Is it possible in an atom to have $12$ protons and $13$ electrons? Explain.
$(c)$ Why is helium gas inert?

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$(a)$ An ion $M^{2+}$ contains $10$ electrons and $12$ neutrons. What is the atomic number and mass number of the element $M$?$(b)$ Is it possible in an atom to have $12$ protons and $13$ electrons? Explain.$(c)$ Why is helium gas inert?