$Al_{2}O_{3}$ was leached with alkali to get $X$. The solution of $X$ on passing of gas $Y$,forms $Z$. $X$,$Y$ and $Z$ respectively are

  • A
    $X = Na[Al(OH)_{4}], Y = SO_{2}, Z = Al_{2}O_{3}$
  • B
    $X = Na[Al(OH)_{4}], Y = CO_{2}, Z = Al_{2}O_{3} \cdot xH_{2}O$
  • C
    $X = Al(OH)_{3}, Y = CO_{2}, Z = Al_{2}O_{3}$
  • D
    $X = Al(OH)_{3}, Y = SO_{2}, Z = Al_{2}O_{3} \cdot xH_{2}O$

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