(B) The number of moles of compound $A$ is calculated as: $n = \frac{\text{mass}}{\text{molar mass}} = \frac{4.5 \ g}{90 \ g/mol} = 0.05 \ mol$. The v

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(B) The number of moles of compound $A$ is calculated as: $n = \frac{\text{mass}}{\text{molar mass}} = \frac{4.5 \ g}{90 \ g/mol} = 0.05 \ mol$. The volume of the solution in liters is: $V = 250 \ mL = 0.250 \ L$. The molarity $(M)$ is given by: $M = \frac{n}{V} = \frac{0.05 \ mol}{0.250 \ L} = 0.2 \ M$. Expressing this in the form $x \times 10^{-1}$: $0.2 = 2 \times 10^{-1}$. Therefore,the value of $x$ is $2$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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$4.5 \ g$ of compound $A$ $(MW = 90)$ was used to make $250 \ mL$ of its aqueous solution. The molarity of the solution in $M$ is $x \times 10^{-1}$. The value of $x$ is ............ (Rounded off to the nearest integer)

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$1$
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$2$
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$3$
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$4$

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Method of expressing concentration of solution

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The mass $\%$ of urea solution is $6$. The total weight of the solution is $1000 \ g$. What is its concentration in $mol \ L^{-1}$? (Density of water $= 1.0 \ g \ mL^{-1}$)
$(C = 12 \ u, N = 14 \ u, O = 16 \ u, H = 1 \ u)$

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The amount of water that should be added to $500 \, mL$ of $0.5 \, N$ solution of $NaOH$ to give a concentration of $10 \, mg$ per $mL$ is (in $, mL$)

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Calculate the molarity of $NaOH$ solution prepared by dissolving $0.4 \ g$ of $NaOH$ in enough water to form $500 \ mL$ of the solution. (in $M$)

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$200 \ mL$ of a solution contains $5.85 \ g$ dissolved sodium chloride. The concentration of the solution will be .......... $molar$ $(Na = 23; Cl = 35.5)$.

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State the various methods of expressing the concentration of a solution.

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$4.5 \ g$ of compound $A$ $(MW = 90)$ was used to make $250 \ mL$ of its aqueous solution. The molarity of the solution in $M$ is $x \times 10^{-1}$. The value of $x$ is ............ (Rounded off to the nearest integer)

Similar Questions

The mass $\%$ of urea solution is $6$. The total weight of the solution is $1000 \ g$. What is its concentration in $mol \ L^{-1}$? (Density of water $= 1.0 \ g \ mL^{-1}$)$(C = 12 \ u, N = 14 \ u, O = 16 \ u, H = 1 \ u)$

The amount of water that should be added to $500 \, mL$ of $0.5 \, N$ solution of $NaOH$ to give a concentration of $10 \, mg$ per $mL$ is (in $, mL$)

Calculate the molarity of $NaOH$ solution prepared by dissolving $0.4 \ g$ of $NaOH$ in enough water to form $500 \ mL$ of the solution. (in $M$)

$200 \ mL$ of a solution contains $5.85 \ g$ dissolved sodium chloride. The concentration of the solution will be .......... $molar$ $(Na = 23; Cl = 35.5)$.

State the various methods of expressing the concentration of a solution.

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The mass $\%$ of urea solution is $6$. The total weight of the solution is $1000 \ g$. What is its concentration in $mol \ L^{-1}$? (Density of water $= 1.0 \ g \ mL^{-1}$)
$(C = 12 \ u, N = 14 \ u, O = 16 \ u, H = 1 \ u)$