RCOCl + 2Me_2NH to A + Me_2NH_2^+Cl^-. Here A | vedclass

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Question

(A) The reaction of an acid chloride $(RCOCl)$ with a secondary amine $(Me_2NH)$ is a nucleophilic acyl substitution reaction. One mole of the seconda

Vedclass · Accepted Answer

$RCON(Me)_2$

Vedclass · Answer

(A) The reaction of an acid chloride $(RCOCl)$ with a secondary amine $(Me_2NH)$ is a nucleophilic acyl substitution reaction. One mole of the secondary amine acts as a nucleophile to attack the carbonyl carbon of the acid chloride,forming an $N,N$-disubstituted amide $(RCON(Me)_2)$. The second mole of the amine acts as a base to neutralize the $HCl$ byproduct,forming the salt $Me_2NH_2^+Cl^-$. The overall reaction is: $RCOCl + 2Me_2NH 	o RCON(Me)_2 + Me_2NH_2^+Cl^-$. Thus,$A$ is $RCON(Me)_2$.

$RCOCl + 2Me_2NH \to A + Me_2NH_2^+Cl^-$. Here $A$ is:

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