L-isomer of tetrose X (C_4H_8O_4) gives posit | vedclass

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(B) $1$. $X$ is a tetrose $(C_4H_8O_4)$ with two chiral carbons and a $-CHO$ group (positive Schiff's test).$2$. Acetylation yields a triacetate,confi

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(B) $1$. $X$ is a tetrose $(C_4H_8O_4)$ with two chiral carbons and a $-CHO$ group (positive Schiff's test).$2$. Acetylation yields a triacetate,confirming three $-OH$ groups.$3$. The $L$-isomer of a tetrose with two chiral centers and the given reactivity corresponds to $L$-threose.$4$. Oxidation of $L$-threose with $HNO_3$ gives $L$-tartaric acid $(A)$.$5$. Reduction of $L$-tartaric acid with $NaBH_4$ gives a chiral compound $(B)$.$6$. Based on the Fischer projection for $L$-threose,the correct structure is represented in option $B$.

List-$I$	List-$II$
$A$. Glucose/$NaHCO_3$/$\Delta$	$I$. Gluconic acid
$B$. Glucose/$HNO_3$	$II$. No reaction
$C$. Glucose/$HI$/$\Delta$	$III$. $n$-hexane
$D$. Glucose/Bromine water	$IV$. Saccharic acid

$L$-isomer of tetrose $X$ $(C_4H_8O_4)$ gives positive Schiff's test and has two chiral carbons. On acetylation,$X$ yields triacetate. $X$ also undergoes the following reactions:
$X$ $\xrightarrow{HNO_3} A$ $\xrightarrow{NaBH_4} \underset{\text{Chiral compound}}{B}$
$X$ is $.......$.

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Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A$. Glucose/$NaHCO_3$/$\Delta$ $I$. Gluconic acid

$B$. Glucose/$HNO_3$ $II$. No reaction

$C$. Glucose/$HI$/$\Delta$ $III$. $n$-hexane

$D$. Glucose/Bromine water $IV$. Saccharic acid

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$L$-isomer of tetrose $X$ $(C_4H_8O_4)$ gives positive Schiff's test and has two chiral carbons. On acetylation,$X$ yields triacetate. $X$ also undergoes the following reactions:$X$ $\xrightarrow{HNO_3} A$ $\xrightarrow{NaBH_4} \underset{\text{Chiral compound}}{B}$$X$ is $.......$.