2-hexene xrightarrow[(i) O_3]{(ii) H_2O} Prod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of $2-$hexene $(CH_3-CH=CH-CH_2-CH_2-CH_3)$ with $O_3$ followed by $H_2O$ is an oxidative ozonolysis.In oxidative ozonolysis,the doub

Vedclass · Accepted Answer

Butanoic acid and acetic acid

Vedclass · Answer

(A) The reaction of $2-$hexene $(CH_3-CH=CH-CH_2-CH_2-CH_3)$ with $O_3$ followed by $H_2O$ is an oxidative ozonolysis.In oxidative ozonolysis,the double bond is cleaved,and the resulting aldehydes are further oxidized to carboxylic acids.$CH_3-CH=CH-CH_2-CH_2-CH_3 \xrightarrow[(i) O_3]{(ii) H_2O} CH_3COOH + CH_3CH_2CH_2COOH$The products formed are acetic acid $(CH_3COOH)$ and butanoic acid $(CH_3CH_2CH_2COOH)$.

$2-$hexene $\xrightarrow[(i) O_3]{(ii) H_2O}$ Products
The two products formed in the above reaction are -

Similar Questions

Which of the following alkyl-substituted alkenes is the most stable?

${\text{Glycerol}}$ $\xrightarrow{KHSO_4} (A)$ $\xrightarrow{LiAlH_4} (B)$; $(A)$ and $(B)$ are respectively:

Cyclohexene on oxidation with $KMnO_4$ in dil. $H_2SO_4$ forms.

The action of water in the presence of sulphuric acid on the following alkenes gives:
$(i)$ $CH_3-CH=C(CH_3)_2$
(ii) $CH_3-CH=CH_2$

In polyenes that contain differently substituted $(C=C)$ double bonds,it is possible to hydrogenate chemoselectively one $(C=C)$ double bond. The product of the reaction of limonene with one mole of $H_2$ in the presence of $PtO_2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$2-$hexene $\xrightarrow[(i) O_3]{(ii) H_2O}$ ProductsThe two products formed in the above reaction are -