Evaluate the expression: frac{2 cdot 3^{n+1} | vedclass

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(A) Given expression: $\frac{2 \cdot 3^{n+1} + 7 \cdot 3^{n-1}}{3^{n+2} - 2 \cdot (\frac{1}{3})^{1-n}}$Rewrite the terms in the numerator and denomina

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(A) Given expression: $\frac{2 \cdot 3^{n+1} + 7 \cdot 3^{n-1}}{3^{n+2} - 2 \cdot (\frac{1}{3})^{1-n}}$Rewrite the terms in the numerator and denominator using $3^{n-1}$ as a common factor:Numerator: $2 \cdot 3^{n+1} + 7 \cdot 3^{n-1} = 2 \cdot 3^{n-1} \cdot 3^2 + 7 \cdot 3^{n-1} = 3^{n-1}(18 + 7) = 25 \cdot 3^{n-1}$Denominator: $3^{n+2} - 2 \cdot (3^{-1})^{1-n} = 3^{n+2} - 2 \cdot 3^{n-1} = 3^{n-1} \cdot 3^3 - 2 \cdot 3^{n-1} = 3^{n-1}(27 - 2) = 25 \cdot 3^{n-1}$Dividing the numerator by the denominator:$\frac{25 \cdot 3^{n-1}}{25 \cdot 3^{n-1}} = 1$

Evaluate the expression: $\frac{2 \cdot 3^{n+1} + 7 \cdot 3^{n-1}}{3^{n+2} - 2 \cdot (1/3)^{1-n}}$

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